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Updated: January 2, 2013 18:52 IST

Azarenka beats Lisicki, reaches Brisbane quarters

AP
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Victoria Azarenka of Belarus waves at the crowd after winning her second round match against Sabine Lisicki of Germany 6-3, 6-3 during the Brisbane International tennis tournament in Australia on Wednesday. Photo: AP
Victoria Azarenka of Belarus waves at the crowd after winning her second round match against Sabine Lisicki of Germany 6-3, 6-3 during the Brisbane International tennis tournament in Australia on Wednesday. Photo: AP

Top-ranked Victoria Azarenka opened her 2013 season with a 6-3, 6-3 win over Germany’s Sabine Lisicki on Wednesday to join No. 3 Serena Williams and fourth-seeded Angelique Kerber in the Brisbane International quarterfinals.

Azarenka, who won here in 2009 without dropping a set, got the better of the No. 37-ranked Lisicki in a match containing nine breaks of serve.

The 23-year-old from Belarus won her first major at the Australian Open last year during a 26-match winning streak to start the season.

Earlier, Angelique Kerber fought back from 5-2 down in the deciding tie-breaker to beat Puerto Rican qualifier Monica Puig, 3-6, 6-4, 7-6 (7) in her second-round match. Sloane Stephens had a 6-3, 6-4 win over Sweden’s Sofia Arvidsson to set up a quarterfinal against fellow American Williams.

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